please help me with this problem!

Answer:
The choice A ;
[tex] \frac{1}{ {7}^{8} } [/tex]
Step-by-step explanation:
[tex] \frac{ {7}^{ - 6} }{ {7}^{2} } = \frac{ {7}^{ - 6 - 2} }{1} = {7}^{ - 8} = \frac{1}{ {7}^{8} } \\ \\ \\ or. \: \frac{ {7}^{ - 6} }{ {7}^{2} } = \frac{1}{ {7}^{ 2 + 6} } = \frac{1}{ {7}^{8} } [/tex]
Hii!
Answer:
Step-by-step explanation:
Use the rule of exponents.
If we divide two numbers with the same bases, we subtract the exponents.
7^-6/7^2=7^-6-2=7^-8
Now, if we have a negative exponent, we flip over the number.
7^-8=1/7^8
Great job!
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Hope that this helped.