Answer: 55[tex]m^{2}[/tex]
Step-by-step explanation:
First find the area of the trapezoid: [tex]\frac{b1 +b2}{2}[/tex](h) : (base 1 + base 2) ÷ 2 x height
base 1 is 5m and we know the other base is parallel to the base of the rectangle so base 2 is 9m.
Since the total height is 7 m and the height of the rectangle is 5 m, subtract to get the height of the trapezoid: 7m - 5m = 2m
put the three values into the equation and solve:
(5m + 9m) ÷ 2 x 2m
(14m) ÷ 2 x 2m
7m x 2m
14[tex]m^{2}[/tex]
Find area of the rectangle which is just base x height
Which is 9m x 5m = 45[tex]m^{2}[/tex]
To find the total area, add the area of the trapezoid and the area of the rectangle. 14[tex]m^{2}[/tex] + 45[tex]m^{2}[/tex] = 55[tex]m^{2}[/tex]
Hope this helps
