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calculate mole fraction of benzene (70 g) having 30 gram of mass of carbon tetrahedral​

Respuesta :

Moles of benzene

  • 70/90=7/9=0.8mol

moles of CCl_4

  • 30/154
  • 0.2mol

Now

[tex]\\ \rm\Rrightarrow \chi_{C_6H_6}[/tex]

[tex]\\ \rm\Rrightarrow \dfrac{\chi_{C_6H_6}}{\chi_{sol^n}}[/tex]

[tex]\\ \rm\Rrightarrow \dfrac{0.8}{0.8+0.2}[/tex]

[tex]\\ \rm\Rrightarrow \dfrac{0.8}{1}[/tex]

[tex]\\ \rm\Rrightarrow 0.8[/tex]

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