It is possible that a small sample size contributed to the 82% (±24%) estimate at a 95% confidence level.
A proportional confidence interval is provided by
[tex]\pi \pm z \sqrt{\frac{\pi (1-\pi )}{n} }[/tex]
Where π is the sample proportion, z is the critical value and n is the sample size.
The margin of error is represented by
[tex]z \sqrt{\frac{\pi (1-\pi )}{n} }[/tex]
As a result, smaller sample sizes result in wider margins of error. Option A has the greater margin of error in this scenario, so it most likely employed the smallest sample size.
Therefore we can conclude It is possible that a small sample size contributed to the 82% (±24%) estimate at a 95% confidence level. Option A is correct.
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