A metallurgist has one alloy containing 26% copper and another one containing 63% copper. How many pounds of alloy must he use to make 58 pounds of a third alloy containing 27% copper

Respuesta :

From the calculations below, 56.43 pounds of 0.26 copper, and 1.57 pounds of 0.63 copper are used.

How do we calculate the amount of copper used?

Let A represents pounds of 0.26 copper and B represents pounds of 0.63 copper are used to make 58 pounds of 0.27 copper.

Therefore, we can use simultaneous equations as follows:

A + B = 58

A = 58 – B ………………………………….. (1)

Also, we have:

0.26A + 0.63B = 0.27 * 58

0.26A + 0.63B = 15.66 ……………………….. (2)

Substituting for A from equation (1) into (2) solve for B, we have:

0.26(58 – B) + 0.63B = 15.66

15.08 – 0.26B + 0.63B = 15.66

0.37B = 15.66 – 15.08

0.37B = 0.58

B = 0.58 / 0.37

B = 1.57 pounds

Substituting for B in equation (1), we have:

A = 58 – 1.57

A = 56.43 pounds

Learn more about simultaneous equations here: https://brainly.com/question/16763389.

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