contestada

Question content area top

Part 1

The circumference of the inner circle is 88 ft. The distance between the inner circle and the outer circle is 3 ft. By how many feet is the circumference of outer circle greater than the circumference of the inner​ circle? Use 22/7

for pi .

Respuesta :

The circumference of the outer circle is greater than that of the inner circle by 18.86 feet.

What is Circle?

A circle is a round 2-dimensional shape. It is a closed shape with a distance from center to circumference termed as radius 'r' and distance from one point on the circumference to another point passing through center termed as diameter 'd'.

The circumference of the inner circle is 88 ft.

Circumference of a Circle  = 2πr

    2πr = 88

   2 X 22/7 X r = 88

     r = 88 X 7 / 44

    r = 14 ft.

Radius of the inner circle = 14 feet

If the distance between the inner circle and the outer circle is 3 ft, the radius of the outer circle = 14+3 = 17 feet.

circumference of the outer Circle = 2πr

                                                         = 2 X 22/7 X 17

                                                         = 106.86 ft.

Difference in Circumference = 106.86 - 88 = 18.86 feet

Thus, the circumference of the outer circle is greater than that of the inner circle by 18.86 feet.

Learn more about Circle from:

https://brainly.com/question/11833983

#SPJ1