The rule for the given graph translation will be; [(x + 6), (y + 1)]
How to carry out Graph Translations?
The Vertices of the quadrilateral ABCD are;
A → (-5, 2)
B → (-3, 4)
C → (-2, 4)
D → (-1, 2)
By reflecting the given quadrilateral ABCD across x-axis to form the image quadrilateral A'B'C'D', the rule for the reflection of a point across x-axis is; (x, y) → (x , -y)
Coordinates of the image point A' will be;
A(-5, 2) → A'(-5, -2)
From the given image, we can see that point E is obtained by translation of point A'.
The rule for the translation of a point by h units right and k units upwards is; A'(x + h, y + k) → E(x', y')
Thus, using this rule, we can say that;
A'(-5 + h, -2 + k) → E(1, -1)
When comparing coordinates of A' and E, we have;
-5 + h = 1
h = 6
-2 + k = -1
k = 1
Thus, we conclude that the rule for the translation will be;
[(x + 6), (y + 1)]
Read more about Graph Translations at; https://brainly.com/question/26238840
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