On a coordinate plane, a parabola opens down. It goes through (negative 3, negative 4), has a vertex at (negative 1, 0), and goes through (1, negative 4). The graph of the function f(x) = –(x + 1)2 is shown. Use the drop-down menus to describe the key aspects of the function. The vertex is the . The function is positive . The function is decreasing . The domain of the function is . The range of the function is

The vertex is at (-1, 0). The function is positive from (-1, ∞). The function is decreasing from (-∞, -1). The domain of the function is (-∞, ∞). The range of the function is (0, -∞).

What is the parabola?

The focus is a non-movable point, while the directrix is a non-movable line.

The equation of a quadratic function, of vertex (h, k), is given by:

y = a(x – h)² + k

where a is the leading coefficient.

The parabola function is given below.

f(x) = –(x + 1)²

The vertex is at (-1, 0). The function is positive from (-1, ∞). The function is decreasing from (-∞, -1). The domain of the function is (-∞, ∞). The range of the function is (0, -∞).

More about the parabola link is given below.

https://brainly.com/question/8495504

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