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A man is heterozygous ( Cc ) for a recessive trait that causes a fatal illness , the mother does not carry the recessive allele ( CC ) . What is the percentage chance of their children being a carrier the trait ?
A.50%
B.25%
C.75%
D.0%
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Respuesta :

Answer: A. 50%

Explanation: If you create a Punnett Square and cross the 2 genotypes, out of the 4 possibilities, 2 will be CC and 2 will be Cc.
50% using a punnet square