The equation that can be solved using [tex]x = \frac{-8 \pm \sqrt{8^2 - 4(3)(-2)}}{2(3)}[/tex] is C. 3x^2 + 8x − 10 = -8
How to determine the equation?
The attached image represents the missing information in the question
From the image, we have:
[tex]x = \frac{-8 \pm \sqrt{8^2 - 4(3)(-2)}}{2(3)}[/tex]
The quadratic formula is:
[tex]x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}}[/tex]
The above means that:
a = 3
b = 8
c = -2
From the list of options, we have:
C. 3x^2 + 8x − 10 = -8
Add 8 to both sides
3x^2 + 8x − 2 = 0
In the above equation, we have:
a = 3
b = 8
c = -2
Hence, the equation that can be solved using [tex]x = \frac{-8 \pm \sqrt{8^2 - 4(3)(-2)}}{2(3)}[/tex] is C. 3x^2 + 8x − 10 = -8
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