(a) The force applied on the box is 98 N.
(b) When you stop pushing, the displacement of the box before coming to rest is 1.02 m.
The force exerted on the box is calculated from Newton's second law of motion.
F - Ff = ma
where;
at constant speed, a = 0
F - Ff = 0
F = Ff
Ff = μmg
Ff = 0.2 x 50 x 9.8
Ff = 98 N
F - Ff = ma
-Ff = ma
a = -Ff/m
a = -98/50
a = - 1.96 m/s²
v² = u² + 2as
when the box stops, v = 0
0 = u² + 2as
0 = (2)² + 2(-1.96)s
0 = 4 - 3.92s
3.92s = 4
s = 4/3.92
s = 1.02 m
When you stop pushing, the displacement of the box before coming to rest is 1.02 m.
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