i dont understand how to do this

The statement EF=2.GF (Option A) and the statement
[tex]\frac{\sqrt{3} }{2} .EF=GE[/tex] (Option C) are true for the ΔEFG.
The six trigonometric ratios of a right-angle triangle are Sin, Cos, Tan, Cosec, Sec and Cot. Trigonometric ratios are used to measure the sides of the right triangle.
Given that in ΔEFG, m∠E=30°, m∠F=60° and m∠G=90°.
Wow, sin 30°[tex]=\frac{GF}{EF}[/tex]
⇒[tex]\frac{1}{2} =\frac{GF}{EF}[/tex]
⇒EF=2.GF
and sin 60°[tex]=\frac{GE}{EF}[/tex]
⇒[tex]\frac{\sqrt{3} }{2} =\frac{GE}{EF}[/tex]
⇒[tex]\frac{\sqrt{3} }{2} .EF=GE[/tex]
Therefore, the statement EF=2.GF (Option A) and the statement [tex]\frac{\sqrt{3} }{2} .EF=GE[/tex] (Option C) are true for the ΔEFG.
To learn more about trigonometric ratios visit:
https://brainly.com/question/1201366.
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