The graph of which function has a
minimum located at (4, -3)?
f(x) = - 4x2 + 4x - 11
f(x) = -2x2 + 16x - 35
f(x) = 4x2-4x + 5
O f(x) = 2x2 - 16x + 35

Respuesta :

The quadratic function that has a minimum located at (4,-3) is given by:

f(x) = 2x² - 16x + 35

What is the vertex of a quadratic equation?

A quadratic equation is modeled by:

[tex]y = ax^2 + bx + c[/tex]

The vertex is given by:

[tex](x_v, y_v)[/tex]

In which:

  • [tex]x_v = -\frac{b}{2a}[/tex]
  • [tex]y_v = -\frac{b^2 - 4ac}{4a}[/tex]

Considering the coefficient a, we have that:

  • If a < 0, the vertex is a maximum point.
  • If a > 0, the vertex is a minimum point.

In this problem, the function has a minimum, which means that a > 0, eliminating the first two options. The x-value of the vertex is of x = 4, hence -b/2a = 4, which means that the function is given by:

f(x) = 2x² - 16x + 35.

More can be learned about quadratic functions at https://brainly.com/question/24737967

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