Given: g ∥ h and ∠2 ≅ ∠3 prove: e ∥ f horizontal and parallel lines e and f are intersected by diagonal and parallel lines g and h. at the intersection of lines g and e, the bottom right angle is angle 2. at the intersection of lines h and e, the bottom right angle is angle 1. at the intersection of lines f and h, the top left angle is angle 3. statements reasons 1. g || h 1. given 2. ∠1 ≅ ∠2 2. corresponding angles theorm 3. ∠2 ≅ ∠3 3. given 4. ∠1 ≅ ∠3 4. transitive property 5. e || f 5. ? what is the missing reason in the proof?

Respuesta :

The missing reason is the Converse alternate interior angles theorem.

What is trigonometry?

The branch of mathematics sets up a relationship between the sides and the angles of the right-angle triangle termed trigonometry.

In the image, you can observe a diagram representing this problem.

We know by given that g||h and ∠2 ≅ ∠3

From the parallelism between line g and line h, we deduct several congruences between angles.

∠2≅∠1, by corresponding angles (same side of the transversal, one interior, the other exterior to parallels).

Now, to demonstrate,e || f we must demonstrate congruence between angle 2 and an angle on the intersection between line g and line f.

In the parallelogram formed, we know

∠2+∠3+180-∠1=360

Where x is the angle at the intersection of line g and line f.

But, we know ∠2≅∠3 and,∠2≅∠1 so

∠2+∠2+180-∠2+x =360

∠2 + x =180

Notice that we don't have a congruence, however, there's a theorem that states that the same-side interior angles of parallels are supplementary.

In this case, we use the corollary of that theorem, which states if two same-side interior angles are supplementary, then the lines are parallels.

e || f

However, according to the choices of the problem, the missing proof is the "converse alternate interior angles theorem", because the problem was demonstrated using transitive property, to show that angles 1 and 3 are congruent, thereby converse alternate interior angles theorem, lines e and f are parallels.

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Answer: d on edg

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