The empirical formula for the compound is [tex]Fe_3PO_4[/tex] if A 8.63 g sample of a compound contains 5.51 g of iron, Fe, 1.02g of phosphorus, P, and oxygen, O.
An empirical formula tells us the relative ratios of different atoms in a compound.
We need to calculate the number of moles:
Given data:
Mass of iron - 5.51 g
Mass of phosphorus -1.02g
Mass of oxygen -2.1 g
Moles of iron - [tex]\frac{mass}{molar \;mass}[/tex]
Moles of iron - [tex]\frac{5.51 g}{56 g/mol}[/tex]
0.098 mole
Moles of phosphorus [tex]-\frac{mass}{molar \;mass}[/tex]
Moles of phosphorus - [tex]\frac{1.02g}{31 g/mol}[/tex]
0.032 moles
Moles of oxygen -[tex]\frac{mass}{molar \;mass}[/tex]
Moles of oxygen - [tex]\frac{2.1 g}{16 g/mol}[/tex]
0.13moles
Dividing each mole using the smallest number that is divided by 0.032moles.
Fe:P:O :: 3:1:4
The empirical formula for the compound is [tex]Fe_3PO_4[/tex].
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