b. The wavelength of light emitted by the object is 233 nm
c. The type of radiation originally emitted by the object is ultraviolet radiation.
To find the wavelength, we need to know what redshift is.
What is redshift?
Redshift is the increase in wavelength and the corresponding decrease of frequency and photon energy of electromagnetic radiation.
Redshift is given by z = λ'/λ - 1 where
- λ' = observed wavelength and
- λ = emitted wavelength.
Making λ subject of the formula, we have
λ = λ'/(1 + z)
Given that has a redshift of 7.6 and the JWST observes the object at a wavelength of 2 micrometres (mid-infrared light).
So,
(b) What is the wavelength of the light emitted by the object?
Substituting the values of the variables into the equation, we have
λ = λ'/(1 + z)
λ = 2μm/(1 + 7.6)
λ = 2μm/8.6
λ = 0.233 μm
λ = 233 nm
So, the wavelength of light emitted by the object is 233 nm
c. What type of radiation was originally emitted by the object?
Since the wavelength is 233 nm and the wavelength is in the range of ultraviolet radiation 200 nm - 315 nm.
So, the type of radiation originally emitted by the object is ultraviolet radiation.
Learn more about redshift here:
https://brainly.com/question/27915180
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