What is the mole fraction of NaBr in
an aqueous solution that contains
20.1% NaBr (weight/weight %)?
Molar Mass
NaBr: 102.89 g/mol
H₂O: 18.016 g/mol
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What is the mole fraction of NaBr in an aqueous solution that contains 201 NaBr weightweight Molar Mass NaBr 10289 gmol HO 18016 gmol Enter text here class=

Respuesta :

Answer:

4.22% NaBr

Explanation:

To find the mole fraction of NaBr, you need to (1) determine the mass of the solute (NaBr) and the solvent (H₂O), then (2) convert the mass of the solute and solvent to moles (via the molar masses), and then (3) calculate the mole fraction of NaBr. The final answer should have 3 sig figs to match the sig figs of the given value (20.1%). Because you are given a percent less than 100%, you can assume that the percent (20.1%) is equal to the mass of the solute (20.1 g).

(Step 1)

100% - 20.1 % NaBr = 79.9% H₂O

20.1% NaBr = 20.1 g NaBr

79.9% H₂O = 79.9 g H₂O

(Step 2)

Molar Mass (NaBr): 102.89 g/mol

20.1 g NaBr              1 mole
-------------------  x  ---------------------  =  0.195 mole NaBr
                                102.89 g

Molar Mass (H₂O): 18.016 g/mol

79.9 g H₂O            1 mole
------------------  x  -------------------  =  4.43 moles H₂O
                              18.016 g

(Step 3)

                                          moles of solute      
Mole Fraction =  ----------------------------------------------------   x 100%
                            moles of solute + moles of solvent
                             

                                            0.195 mole NaBr
Mole Fraction =  --------------------------------------------------------  x 100%
                            (0.195 mole NaBr) + (4.43 moles H₂O)

Mole Fraction  =  4.22% NaBr

Answer:

0.0422

Explanation:

Right on Acellus