When passing in a medium for a distance of 1.5 cm intensity

of the light decreased by 3 times. What will the distance x equal to when the intensity of the light decreases by 9 times?

Respuesta :

The distance x equal to 0.87 cm when the intensity of the light decreases by 9 times.

Intensity of light

The intensity of light is given as power emitted by the light by unit area.

I = P/A

I = P/L²

I₁L₁² = I₂L₂²

L₂² = I₁L₁²/I₂

L₂² = (3 x 1.5²)/(9)

L₂² = 0.75

L₂ = 0.87 cm

Thus, the distance x equal to 0.87 cm when the intensity of the light decreases by 9 times.

Learn more about intensity here: https://brainly.com/question/14924672

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