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the 3kg object in figure is released from rest at height of 5m on curved frictionless ramp.at the foot of the ramp is a spring of force constant 400N/m.the object slide down the ramp and into the spring, compressing it a distance x before coming momentarily to rest. a) find x
b)describe the motion of the object (if any) after the block momentarily comes to rest?

Respuesta :

Eduard22sly

The value of x given the data from the question is 0.86 m

How to determine the energy

From the data given above, we can s determine the energy as follow:

  • Mass (m) = 3 Kg
  • Height (h) = 5 m
  • Acceleration due to gravity (g) = 9.8 m/s²
  • Energy (E) = ?

E = mgh

E = 3 × 9.8 × 5

E = 147 J

How to determine the value of x

  • Spring constant (K) = 400 N/m
  • Energy (E) = 147 J
  • Extention (e) = x = ?

E = ½Ke²

147 = ½ × 400 × x²

147 = 200 × x²

Divide both side by 200

x² = 147 / 200

Take the square root of both sides

x = √( 147 / 200)

x = 0.86 m

Since the block came to rest, there is no motion

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