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What are the solutions to the quadratic equation below in factored form?
(2x - 1)(3x + 4) = 0
0x=
0x =
O
X =
2
16
-
x =
x =
29
3|4
x = = 1/1, X =
2
4/3
x = − 1/1
1
حرا من

Respuesta :

Itz5151

Answer:

[tex]\cfrac{-4}{3} [/tex] and [tex]\cfrac{1}{2} [/tex].

Step-by-step explanation:

Equation:

[tex] \rm \: \: (2x - 1)(3x + 4) = 0[/tex]

Solution:

Set factors equal to zero,that is:

[tex](2x - 1) = 0 \: \: \: \: \: \: \: \: \: \: \: ...(1)[/tex]

[tex](3x + 4) = 0 \: \: \: \: \: \: \: \: \: \: \: \: ...(2)[/tex]

Solving for equation 1:

  • [tex]2x - 1 = 0[/tex]
  • [tex]2x = 0 + 1[/tex]
  • [tex]2x = 1[/tex]

  • [tex] \boxed{x = \cfrac{ 1}{2} }[/tex]

Solving for equation 2:

  • [tex]3x + 4 = 0[/tex]
  • [tex]3x = 0 - 4[/tex]
  • [tex]3x = - 4[/tex]

  • [tex]\boxed{x = \cfrac{ - 4}{3} }[/tex]

Hence,the solutions to the quadratic equation in factored form is [tex]\cfrac{-4}{3} [/tex] and [tex]\cfrac{1}{2} [/tex].

[tex]\rule{225pt}{2pt}[/tex]

Good luck on your assignment!

FANofVectorFundament

Answer:

-4/3 or 1/2

Step-by-step explanation:

Explanation::::::::

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