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What temperature, in Kelvin, does a 1.00 gram sample of Ne in a 2.50 L container need to be adjusted to in order to bring the pressure to 1.00 atm? Report your answer to the nearest Kelvin. (Moodle is looking for a number only, no units.)

Respuesta :

The temperature of 0.049 moles of a Ne with a pressure of 1.00 atm and a volume of 2.50 L is 621.44K.

How to calculate temperature?

The temperature of a given gas can be calculated using the ideal gas law equation:

PV = nRT

Where;

P = pressure = 1.00 atm

V = volume =2.50 L

R = gas law constant = 0.0821 Latm/molK

Mass =1.00 gram

The molar mass of Ne= 20.1797 u

[tex]Moles = \frac{mass}{molar \;mass}[/tex]

[tex]Moles = \frac{1.00}{20.1797}[/tex]

Moles = 0.049mol

T = temperature=?

Putting the value in the equation:

PV = nRT

1.00 atm × 2.50 L = 0.049mol × 0.0821 × T

T = 621.44K

Therefore, the temperature of 0.049 moles of a Ne with a pressure of 1.00 atm and a volume of 2.50 L is 621.44K.

Learn more about the temperature at:

brainly.com/question/11464844

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