Answer:
[tex]x=(-2,\frac{5}{3} )[/tex]
Step-by-step explanation:
1) We will use the matrix method to solve this problem.
[tex]\left[\begin{array}{ccc}-2/3&1&3\\1&0&-2\\\end{array}\right][/tex]
2) Swap Row₁ and Row₂ to make row reduction easier.
[tex]\left[\begin{array}{ccc}1&0&-2\\-2/3&1&3\\\end{array}\right][/tex]
3) Apply to Row₂ : Row₂ + [tex]\frac{2}{3}[/tex] Row₁.
[tex]\left[\begin{array}{ccc}1&0&-2\\0&1&5/3\end{array}\right][/tex]
4) Simplify rows.
[tex]\left[\begin{array}{ccc}1&0&-2\\0&1&5/3\\\end{array}\right][/tex]
Note: The matrix is now in row echelon form.
The steps below are for back substitution.
5) Apply Row₁ : Row₁ - 0 Row₂.
[tex]\left[\begin{array}{ccc}1&0&-2\0\\0&1&5/3\end{array}\right][/tex]
6) Simplify rows.
[tex]\left[\begin{array}{ccc}1&0&-2\\0&1&5/3\\\end{array}\right][/tex]
Note: The matrix is now in reduced row echelon form.
7) Therefore,
[tex]x=-2\\x=\frac{5}{3}[/tex]
