Respuesta :
[tex] \frac{ - 3}{5} \\ [/tex]
because , in the third quadrant , the value of cos is negative. Moreover , we can find the third side of the triangle using Pythagoras theorem.
then ,
[tex] \cos(\theta) = \frac{base}{hypotenuse} \\ \\ \dashrightarrow \: \cos(\theta) = \frac{ - 3}{5} [/tex]
hope helpful.
The answer is cos 0 = -3/5
To calculate the answer:
Given :
tan 0 = 4/3 and is in the 3rd quadrant
this implies that both the perpendicular and base are negative.
Perpendicular = -4
Base = -3
Hypotenuse = [tex]\sqrt{(perpendicular)^{2} + (base)^{2} }[/tex]
Hypotenuse = [tex]\sqrt{(-4)^{2} + (-3)^{2} }[/tex]
Hypotenuse = [tex]\sqrt{25} = 5[/tex]
cos 0 = [tex]\frac{Base}{Hypotenuse}[/tex]
cos 0 = -3/5
Therefore, cos 0 = -3/5
To learn more about trigonometric functions refer to :
https://brainly.com/question/25618616
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