Answer: See below
Explanation:
a) Using Newton's 2nd Law, rearranging and solving for acceleration
[tex]a &= \frac{F}{m}\\ &= \frac{25\ \text{N}}{0.5\ \text{kg}}\\ &= \boxed{50\ \text{m/s}^2}[/tex]
b) Using the acceleration 50 m/s^2 and the initial velocity v = 0 (since the object starts from rest), the final velocity at t = 20, v can be determined using a suitable equation as follows:
[tex]v &= u+ at\\ &= 0+ 50\ \text{m/s}^2(20\ \text{s})\\ &= \boxed{100\ \text{m/s}}[/tex]
c) To determine the distance s traveled in the 20 seconds, we'll use a suitable equation:
[tex]s &= ut+\frac{1}{2}at^2\\ &= 0+\frac{1}{2}(50 \text{m/s}^2)(20\ \text{s})^2\\ &= \boxed{10\ 000\ \text{m}}[/tex]
