Distance formula: StartRoot (x 2 minus x 1) squared + (y 2 minus y 1) squared EndRoot

Does the point (1, StartRoot 7 EndRoot) lie on the circle shown?
Explain.

Yes, the distance from (–2, 4) to (1, ) is 4 units.
Yes, the distance from (–2, 0) to (1, StartRoot 7 EndRoot) is 4 units.
No, the distance from (–2, 0) to (1, StartRoot 7 EndRoot) is not 4 units.
No, the distance from (–2, 4) to (1, StartRoot 7 EndRoot) is not 4 units.

Respuesta :

Yes, the distance from (-2, 0) to (1, √7) is 4 units.

How to Interpret the Equation of a Circle?

We know that the general form of equation of the circle is given by;

(x - h)² + (y - k)² = r²

where;

(h, k) is the coordinate of the center

r is the radius

From the attached image, the radius is equal to the distance between the center and the point (-2,4).  Thus, r = 4 and so we have;

(x + 2)² + (y - 0)² = 4²

(x + 2)² + y² = 16

If the distance between the center and the point is equal to the radius of the circle , then the point lies on the circle and the formula to calculate the distance between two points is;

d = √[(y₂ - y₁)² + (x₂ - x₁)²]

At A(-2, 0) and B(1, √7), we have;

d = √[(√7 - 0)² + (1 - (-2))²]

d = 4 units

Therefore we can conclude that  the distance from (-2, 0) to (1, √7) is 4 units.

Read more about Circle Equation at; https://brainly.com/question/1559324

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