The value of the expression will be 2. Then the correct option is B.
The complete question is given below.
What is the limit?
The value that approaches the output for the given input value. Limits are a very important tool in calculus.
The expression is given below.
[tex]\rightarrow \displaystyle \lim_{x \to 0}\dfrac{\cos x \ \tan 2x}{x}[/tex]
Then the value of the expression will be
Applying L'hospital rule, then we have
[tex]\rightarrow \displaystyle \lim_{x \to 0}\dfrac{\dfrac{d}{dx} \cos x \ \tan 2x}{\dfrac{d}{dx}x}\\\\\\\\\rightarrow \displaystyle \lim_{x \to 0}\dfrac{2 \cos x \sec^2 2x - \sin x \ \tan 2x}{1}\\[/tex]
Put the limit, then we have
⇒ 2 × cos 0 × sec² (2 × 0) – sin 0 × tan (2 × 0)
⇒ 2 × 1 × 1 – 0
⇒ 2
Then the correct option is B.
More about the limit link is given below.
https://brainly.com/question/8533149
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