Step-by-step explanation:
Let, the given point of the equation of the line are (3,-1) and (0,3) i.e
(x1,y1)=(3,-1) and (x2,y2) = (0,3)
Now,
The slope of the line (m1) = y2-y1 ÷ x2-x1
= 3-(-1) ÷ 0-3
= 3+1 ÷ -3
= 4/-3
since, the lines are parallel i.e.
m1 = m2
or, m2 = -4/3
Again,
The required equation of the line passing through the point (-3,2)=(x1,y2) is
y-y1 = m2(x-x1)
or, y-2 = -4/3 ( x +3)
or, 3(y-2) = -4(x+3)
or, 3y-6 = -4x - 12
or, 4x+3y = -12+6
Therefore, 4x+3y = -6 is the right answer.
