The molar ratio in which 3 metal ions are liberated at electrode is 6 : 3 : 2.
An electrolytic cell is one in which energy is produced by a non-spontaneous chemical process.
Given that number of moles of metals released by each is given by the equations;
1) Ag^+(aq) + e -----> Ag(s)
2) Ca^2+(aq) + 2e ---- Ca(s)
3) Al^3+(aq) + 3e -----> Al(s)
It then follows that the ratio of the ions for the passage of 1F is; 1 : 1/2 : 1/3 or 6 : 3 : 2.
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