A copper wire of diameter 3.256mm carries a current of 6.25mA. the potential difference is mathematically given as
V=2.0657*10^{-4}
What is the potential difference across a 200m length of the wire?
Generally, the equation for is mathematically given as
R=Pl/A
Therefore
R=1.72*10^{-8}*2.00/\pi*(1.628)^2*10^{-6}
R=1.652*10^{-2}
In conclusion,
V=IR
V=12.5*10^{-3}*1.652*10^{-2}
V=2.0657*10^{-4}
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