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A satellite is in a circular orbit very close to the surface of a spherical planet. The period of the orbit is 2.35 hours. What is density of the planet? Assume that the planet has a uniform density.

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onyebuchinnaji

The density of the planet is determined as 1,974.26 kg/m³.

Density of the planet

√(⁴/₃πGρ) = 2π/(2.35 x 3600)

where;

  • ρ is density of the planet
  • G is universal gravitation constant

√(⁴/₃πGρ) = 2π/(2.35 x 3600)

√(⁴/₃πGρ) = 2π/8460

(⁴/₃πGρ)  = (2π/8460)²

⁴/₃πGρ = 4π²/(8460)²

ρ = 12π/(8460² x 4G)

ρ = (12π) / (8460² x 4 x 6.67 x 10⁻¹¹)

ρ = 1,974.26 kg/m³

Thus, the density of the planet is determined as 1,974.26 kg/m³.

Learn more about density here: https://brainly.com/question/6838128

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