The Empirical formula of compound is C₁H₂O₁. The Molecular Formula of the compound is 4 (C₁H₂O₁).
Empirical formula is the simplest whole number ratio of atoms present in given compound.
Element % Atomic mass Relative no. of atoms Simplest whole ratio
C 40.6 12 [tex]\frac{40.6}{12}[/tex] = 3.3 [tex]\frac{3.3}{3.3} = 1[/tex]
H 5.1 1 [tex]\frac{5.1}{1}[/tex] = 5.1 [tex]\frac{5.1}{3.1} = 2[/tex]
O 54.2 16 [tex]\frac{54.2}{16}[/tex] = 3.3 [tex]\frac{3.3}{3.3} = 1[/tex]
The Empirical formula of compound is C₁H₂O₁ or CH₂O
Molecular formula = Empirical formula × n
[tex]n = \frac{\text{Molecular weight}}{\text{Empirical Formula weight}}[/tex]
[tex]= \frac{118.084}{30}[/tex]
= 4
Molecular formula = n × Empirical formula
= 4 (C₁H₂O₁)
Thus from the above conclusion we can say that The Empirical formula of compound is C₁H₂O₁. The Molecular Formula of the compound is 4 (C₁H₂O₁).
Learn more about the Empirical Formula here: brainly.com/question/1603500
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