Given that, y varies indirectly as the square of x, the value of y when x equal 8 is 2.
What is the value of y when x equal 8?
Indirect variation is expressed as;
y ∝ 1/x
Given that;
y ∝ 1/x²
y = k/x²
Where k is the proportionality constant.
Given that;
First, we determine the proportionality constant.
y = k/x²
8 = k/4²
8 = k/16
k = 128
Now, we find y when x = 8
y = k/x²
y = 128 / 8²
y = 128 / 64
y = 2
Given that, y varies indirectly as the square of x, the value of y when x equal 8 is 2.
Learn more about proportionality here: brainly.com/question/11202658
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