12.) tan L
A)
C)
√6
2
√6
w
L
√
V10
B)
D)
2
√6
√10
2
√10
M
N

Answer: [tex]\frac{\sqrt{6}}{2}[/tex]
Step-by-step explanation:
By the Pythagorean theorem,
[tex]2^2 + (MN)^2 = (\sqrt{10})^2\\\\4+(MN)^2 = 10\\\\(MN)^2 = 6\\\\MN=\sqrt{6}\\\\\implies \tan L=\frac{\sqrt{6}}{2}[/tex]