A sample of propane (C3H8) has a mass of 0.47 g. The sample is burned in a bomb calorimeter that has a mass of 1.350 kg and a specific heat of 5.82 J/(g • °C). How much energy is released by the reaction if the temperature of the calorimeter rises by 2.87°C?
Use q equals m C subscript p Delta T..
7.85 kJ
10.6 kJ
22.5 kJ
47.9 kJ

Question

21-07-2022
Chemistry

contestada

A sample of propane (C3H8) has a mass of 0.47 g. The sample is burned in a bomb calorimeter that has a mass of 1.350 kg and a specific heat of 5.82 J/(g • °C). How much energy is released by the reaction if the temperature of the calorimeter rises by 2.87°C?
Use q equals m C subscript p Delta T..
7.85 kJ
10.6 kJ
22.5 kJ
47.9 kJ

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dsdrajlin dsdrajlin · Answer 1 · 2022-07-22T22:42:34+02:00

Propane is burned in a 1.350-kg bomb calorimeter with a specific heat of 5.82 J/g.°C. For a temperature rise of 2.87 °C, the energy released is 22.5 kJ.

What is a bomb calorimeter?

It is a device that can measure heats of combustion, used in various applications such as calculating the calorific value of foods and fuels.

A sample of propane is burned in a bomb calorimeter with a mass (m) of 1.350 kg and a specific heat (c) of 5.82 J/g.°C. All the energy released by the propane is absorbed by the bomb calorimeter.

If the temperature rises by 2.87 °C (ΔT), we can calculate the energy released (Q) using the following expression.

Q = c × m × ΔT = 5.82 J/g.°C × 1,350 g × 2.87 °C × (1 kJ/1000 J)

Q = 22.5 kJ

Propane is burned in a 1.350-kg bomb calorimeter with a specific heat of 5.82 J/g.°C. For a temperature rise of 2.87 °C, the energy released is 22.5 kJ.

Learn more about bomb calorimeters here: https://brainly.com/question/9360310

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