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According to the Rational Root Theorem, the following are potential roots of f(x) = 2x2 + 2x – 24.

–4, –3, 2, 3, 4

Which are actual roots of f(x)?
–4 and 3
–4, 2, and 3
–3 and 4
–3, 2, and 4

Respuesta :

MrRoyal

The actual roots of f(x) are -4 and 3

How to determine the actual roots?

The function is given as:

f(x) = 2x^2 + 2x – 24.

Expand the function

f(x) = 2x^2 + 8x- 6x – 24.

Factorize the function

f(x) = 2x(x + 4) - 6(x + 4)

Factor out x + 4

f(x) = (x + 4)(2x - 6)

Set to 0

(x + 4)(2x - 6) = 0

Solve for x

x = -4 and 2x = 6

This gives

x = -4 and x = 3

Hence, the actual roots of f(x) are -4 and 3

Read more about actual roots at:

https://brainly.com/question/20896994

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