1. The mass of Fe2O3 required will be 51.29 grams
2. The mass of Cu that will be formed is 36 kg
Stoichiometric problems
1) The equation of the reaction goes thus: [tex]2Fe_2O_3 + 3Pt --- > 3PtO_2 + 4Fe[/tex]
Mole ratio of Fe to Fe2O3 = 2:1
Mole of 35.9 g Fe = 35.9/56 = 0.6411 mol
Equivalent mole of Fe2O3 = 0.6411/2 = 0.3205 mol
Mass of 0.3205 mol Fe2O3 = 0.3205 x 160 = 51.29 grams
2) [tex]2CuO --- > 2Cu + O_2[/tex]
Mole ratio of CuO to Cu = 1:1
Mole of 45 kg CuO = 45000/80 = 562.5 mol
Equivalent mole of Cy = 562.5 mol
Mass of 562.5 mol of Cu = 562.5 x 64 = 36,000 grams or 36 kg
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