There are 20 $5 bills and 10 $2 coins.
He bought a radio for $120. He paid for it with 2 coins and $5 bills.
let
the number of $5 bills = x
the number of $2 coins = y
Therefore,
y = 1 / 2 x
2y + 5x = 120
2(1 /2 x) + 5x = 120
x + 5x = 120
6x = 120
x = 120 / 6
x = 20
y = 1 / 2 × 20
y = 10
Therefore, there are 20 $5 bills and 10 $2 coins.
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