contestada

If f(x)f(x) is an exponential function where f(3.5)=12f(3.5)=12 and f(9)=75f(9)=75, then find the value of f(7.5)f(7.5), to the nearest hundredth.

Respuesta :

Using an exponential function, it is found that f(7.5) = 45.5.

What is an exponential function?

An exponential function is modeled by:

[tex]y = ab^x[/tex].

In which:

  • a is the initial value.
  • b is the rate of change.

For this problem, we have that f(3.5) = 12, then:

[tex]y = ab^x[/tex]

[tex]12 = ab^{3.5}[/tex]

[tex]a = \frac{12}{b^{3.5}}[/tex]

We also have that f(9) = 75, then:

[tex]y = ab^x[/tex]

[tex]75 = ab^9[/tex]

Since [tex]a = \frac{12}{b^{3.5}}[/tex]:

[tex]75 = \frac{12}{b^{3.5}} \times b^9[/tex]

[tex]b^{5.5} = \frac{75}{12}[/tex]

[tex]\sqrt[5.5]{b^{5.5}} = \sqrt[5.5]{\frac{75}{12}}[/tex]

[tex]b = \left(\frac{75}{12}\right)^{\frac{1}{5.5}[/tex]

b = 1.39542165

Then:

[tex]75 = ab^9[/tex]

[tex]a = \frac{75}{1.39542165^9}[/tex]

a = 3.7386

Hence:

[tex]y = 3.7386(1.39542165)^x[/tex]

When x = 7.5, we have that:

[tex]y = 3.7386(1.39542165)^{7.5} = 45.5[/tex]

Hence f(7.5) = 45.5.

More can be learned about exponential functions at https://brainly.com/question/25537936

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