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A coin slides over a frictionless plane and across an xy coordinate system from the origin to a point with xy coordinates (3.0 m, 4.0 m) while a constant force acts on it. The force has magnitude 2.0 N and is directed at a counterclockwise angle of 100 from the positive direction of the x axis. How much work is done by the force on the coin during the displacement

Respuesta :

Work done by the force is 6.802 Joule

Given:

Therefore displacement of coin along x axis,x=3m

displacement of coin along y-axis,y=4m

force has magnitude = 2.0 N

To Find:

Work done by the force

Solution: Work is done whenever a force moves something over a distance. You can calculate the energy transferred, or work done, by multiplying the force by the distance moved in the direction of the force.

component of force along x-axis, F = 2.0Ncos100

F = 2x(-.173)

F = -(.346)N

component of force in y direction,F₁ = 2.0sin100

F = 2x(.98)

F = 1.96N

work is done by the force on the coin during the displacement will be given as

W = Fx*x + Fy*y

W = -(.346) x 3m + 1.96 x 4

W = 6.802 Joule

Hence, Work done by the force is 6.802 Joule

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