(a) The normal force exerted by the road on the car is 8,506.2 N.
(b) The normal force exerted by the car on the driver is 394.9 N.
(c) The speed of the car at which the normal force on driver is zero is 29.2 m/s.
Normal force exerted by the road on the car
The normal force exerted by the road on the car is calculated as follows;
Normal force = weight of the car - centripetal force of car
Weight of the car = (1400 x 9.8) = 13,720 N
Centripetal force of the car = (1400 x 18²)/87 = 5,213.8 N
Normal force = 13,720 N - 5,213.8 N
Normal force = 8,506.2 N
Normal force exerted on the driver
Normal force = weight of driver - centripetal force of driver
Weight of driver = (65 x 9.8) = 637 N
Centripetal force of driver = (65² x 18²)/(87) = 242.07 N
Normal force = 637 N - 242.07 N = 394.9 N
Speed at which normal force on driver is zero
N = mg - mv²/r
0 = mg - mv²/r
mv²/r = mg
v²/r = g
v² = rg
v = √rg
v = √(87 x 9.8)
v = 29.2 m/s
Thus, the normal force exerted by the road on the car is 8,506.2 N.
The normal force exerted by the car on the driver is 394.9 N.
The speed of the car at which the normal force on driver is zero is 29.2 m/s.
Learn more about normal force here: https://brainly.com/question/14486416
#SPJ1
