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The 0.20 kg puck on the frictionless, horizontal table in the figure is connected by a string through a hole in the table to a hanging 1.20 kg block.(Figure 1)

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onyebuchinnaji

The speed with which the puck must rotate in the circular path is 5.42 m/s.

Speed of the puck in circular path

The speed of the puck is calculated as follows;

centripetal force = weight of hanging mass

mv²/r = W

where;

  • W is weight of the hanging mass
  • m is mass of the puck
  • r is radius of the circular path

v² = Wr/m

v² = (1.2 x 9.8 x 0.5) / (0.2)

v² = 29.4

v = √29.4

v = 5.42 m/s

Thus, the speed with which the puck must rotate in the circular path is 5.42 m/s.

The complete question is below:

With what speed must the puck rotate in a circle of radius 0.50 m if the block is to remain hanging at rest?

Learn more about circular path here: https://brainly.com/question/15457645

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