The possible values of x according to the give. equation are; 0, ±√3i, ±2i, i, -1.
What are the possible values of x?
The possible values of x in the equation given in the task content represent the zeroes of the equation and can be determined as follows;
(x²+3) (x³+4x) (x²+x-i-xi) = 0.
Hence, by further factorisation; we have;
x(x²+3) (x²+4) (x-i) (x+1) = 0.
The possible values of x are therefore;
x = 0;
x²+3 = 0; x = ±√3i
x² +4 = 0; x = ±2i
x -i = 0; x = i.
x +1 = 0; x = -1
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