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An electron gun shoots electrons at a metal plate that is 4.0 mm away in a vacuum. The plate is 5.0 V lower in potential than the gun. How fast must the electrons be moving as they leave the gun if they are to reach the plate?

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pstnonsonjoku

The speed of the electron is 1.3 * 10^6 m/s

What is the velocity?

We know that when the electron gun is shot, the potential energy of the electron is converted into kinetic energy. The mass of the electron is given as 9.11 * 10^-31 Kg.

The energy of the electron is;

eV = 1e * 5V = ev or 8 * 10^-19 J

Given that E = 1/2mv^2

8 * 10^-19  = 0.5 *  9.11 * 10^-31 * v^2

v = √ 8 * 10^-19/0.5 *  9.11 * 10^-31

v = √1.75 * 10^12

v = 1.3 * 10^6 m/s

Learn ore about speed of electron:https://brainly.com/question/13130380

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