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A uniform bar 15m long balanced on a pivot at its midpoint. A boy of mass 55kg sits on one arm of the bar at a point 5m away from the pivot. What mass can be placed 2m away from the other end of the bar to keep the bar horizontally

Respuesta :

The mass at the other end of bar will be 50g .

what is mass

It is the fundamental property of matter , every single property which exist in this world has mass

Mass never can be 0 .

So , the system is in equilibrium

let mass of the body be m

55×5= m×5.5

m= 5 5 × 5 /. 5.5

m= 5 0g



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The answer is 137.5 kg.

What does horizontal mean?

  • Any straight line traveling from left to right or right to left is a horizontal line. If two points on a line share the same Y-coordinates, the line is said to be horizontal in coordinate geometry. It is derived from the word "horizon." In other words, the horizon or x-axis is always parallel to the horizontal lines.
  • In the coordinate plane, a horizontal line is a straight line drawn from right to left or from left to right, perpendicular to the x-axis. In other words, a horizontal line is a straight line with an intercept solely on the y-axis, not the x-axis.

To keep the bar horizontal, the right and left side torques must be equal:

[tex]F_{1} d_{1} =F_{2} d_{2}[/tex]

[tex]F_{2} =F_{1} \frac{d_{1} }{d_{2} }[/tex]

    [tex]=(55.9.8)\frac{5}{2}[/tex]

    =1347.5 N.

Convert this force of gravity into mass:

[tex]F_{2} =m_{2} g,[/tex]

[tex]m_{2} =\frac{F_{2} }{g}[/tex]

     [tex]=\frac{1347.5}{9.8}[/tex]

     =137.5 kg.

The answer is 137.5 kg.

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