The plane is tiled by congruent squares of side length $a$ and congruent pentagons of side lengths $a$ and $\frac{a\sqrt{2}}{2}$, as arranged in the diagram below. The percent of the plane that is enclosed by the pentagons is closest to (A) 50 (B) 52 (C) 54 (D) 56 (E) 58

Respuesta :

Lanuel

The percentage of this plane that's enclosed by the pentagons is closest to: D. 56.

How to determine the percentage?

Since the side of the small square is a, then the area of the tile is

given by:

Area of tiles = 9a²

Note: With an area of 9a², 4a² is covered by squares while 5a² by pentagons.

This ultimately implies that, 5/9 of the tiles are covered by pentagons and this can be expressed as a percentage as follows:

Percent = 5/9 × 100

Percent = 0.555 × 100

Percent = 55.5 56%.

Read more on area of square here: https://brainly.com/question/8902873

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Complete Question:

The plane is tiled by congruent squares of side length a and congruent pentagons of side lengths a and a²/a, as arranged in the diagram below. The percent of the plane that is enclosed by the pentagons is closest to (A) 50 (B) 52 (C) 54 (D) 56 (E) 58

Ver imagen Lanuel