Consider the chemical equation in equilibrium. CH4(g) H2O(g) CO(g) 3H2(g) What will happen to the equilibrium of this reaction if the pressure is increased

Respuesta :

The equilibrium of this reaction will shift to the left to favor the reverse reaction if the pressure is increased.

Balanced chemical equation

CH₄(g) + H₂O(g)  → CO(g) + 3H₂(g)

The principle suggests

The equilibrium will move to the side of the reaction where there are fewer moles of gas as pressure increases.

And the equilibrium will move toward the side of the reaction where there are more gas molecules when the pressure is reduced.

In the given chemical equation

The no. of moles of reactant = 2

The no of moles of the product = 4

Total moles of reactant is less than that of total moles of product

Therefore, If the pressure is increased the equilibrium of this reaction will shift to the left to favor the reverse reaction.

Learn more about Le Ch-atilier's principle here https://brainly.com/question/3384381

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