A weather balloon calibrated at 0.00 °C to
have a volume of 20.0 L has what volume at
-36.2 °C assuming pressure is held
constant? Answer is in L

Respuesta :

Answer:

17.3 L

Explanation:

With all other variables held constant, you can find the missing volume using the Charles' Law equation:

V₁ / T₁ = V₂ / T₂

In this equation, "V₁" and "T₁" represent the initial volume and temperature. "V₂" and "T₂" represent the final volume and temperature. Before we can solve, we need to convert Celsius to Kelvin (because we don't want negative numbers or temp. of 0).

V₁ = 20.0 L                                            V₂ = ? L

T₁ = 0.00 °C + 273.15 = 273.15 K         T₂ = -36.2 °C + 273.15 = 236.95 K

V₁ / T₁ = V₂ / T₂                                             <----- Charles' Law equation

20.0 L / 273.15 K = V₂ / 236.95 K               <----- Insert values

0.0732 = V₂ / 236.95 K                               <----- Simplify left side

17.3 L = V₂                                                   <----- Multiply both sides by 236.95