The required equation for a line passing through point A and perpendicular to BC exists 2y + 5x = 31.
First, we must obtain the slope of the line perpendicular to BC
Given the coordinates B(7,5), and C(2,3)
Get the slope BC, exists
[tex]$m_{BC} = \frac{3-5}{2-7}[/tex]
= -2/-5 = 2/5
The slope of the line perpendicular to BC will be -5/2.
The slope of the required line in point-slope form exists expressed as;
[tex]$y - y_0 = m(x - x_0)[/tex]
m = -5/2
[tex](x_0, y_0) = (3, 8)[/tex]
Substitute the values into the formula we get
y - 8 = (-5/2)(x - 3)
2(y - 8) = (-5)(x - 3)
2y - 16 = (-5x + 15)
2y + 5x = 15 + 16
2y + 5x = 31
Therefore the required equation for a line passing through point A and perpendicular to BC exists 2y + 5x = 31.
To learn more about the slope of the line refer to:
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