The probability of all three events happening when the dies are rolled is; 0.0083
A) On the first die, it has 6 sides and 3 must come out, that is, 1 event out of 6 possible, therefore the probability is: 1/6
B) On the second die, it has 20 sides and if 19 or 20 can come out, that is 2 events out of 20 possible, so the probability is: 2/20 = 1/10
C) On the third die, which is 12 sides, an odd number can come out. The odd numbers would be 1, 3, 5, 7, 9, 11; i.e, 6 events out of 12 possible numbers.
Thus, the probability would be: 6/12 = 1/2
The final probability would be;
(1/6) * (1/10) * (1/2) = 0.0083
Read more about Probability of rolling a Die at; https://brainly.com/question/14192140
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