Respuesta :
The surface area of the closed box in terms of l only, which has the square base is,[tex]2l^2 + \frac{116}{l}[/tex]
How to determine the surface area
The volume of cuboid or box can be given as,
Volume = l × b × h
Here, (l) is the length, (b) is the width of the box and (h) is the height of the box.
A closed box has a square base with side length l feet and height h feet. Therefore, the length and width will be the same.
Then the volume of the box is 29 cubic feet. Thus,
29 = l × l × h
29 = [tex]l^2 h[/tex]
[tex]h = \frac{l^2}{29}[/tex]
The surface area of the square base box is,
Area = [tex]2l^2 + 4lh[/tex]
Substitute the value of h
Area = [tex]2l^2 + 4l\frac{29}{l^2}[/tex]
Area = ,[tex]2l^2 + \frac{116}{l}[/tex]
Therefore, the surface area of the closed box in terms of l only, which has the square base is,[tex]2l^2 + \frac{116}{l}[/tex]
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